ALGORITHM/PROGRAMMERS
[프로그래머스] 행렬의 곱셈
0298
2021. 7. 30. 22:18
https://programmers.co.kr/learn/courses/30/lessons/12949#
코딩테스트 연습 - 행렬의 곱셈
[[2, 3, 2], [4, 2, 4], [3, 1, 4]] [[5, 4, 3], [2, 4, 1], [3, 1, 1]] [[22, 22, 11], [36, 28, 18], [29, 20, 14]]
programmers.co.kr
2021-07-30
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
|
class Solution {
public int[][] solution(int[][] arr1, int[][] arr2) {
int[][] answer = new int[arr1.length][arr2[0].length];
for(int i = 0; i < arr1.length; i++) {
for(int k = 0; k < arr2[0].length; k++) {
for(int j = 0; j < arr1[i].length; j++) {
answer[i][k] += arr1[i][j]*arr2[j][k];
}
}
}
return answer;
}
}
|
cs |
#문제풀이
행렬의 곱셈
A B = AB
(i x j) (j x k) (i x k)