ALGORITHM/PROGRAMMERS
[프로그래머스] 카카오프렌즈 컬러링북 (2017 카카오코드 예선)
0298
2021. 6. 27. 21:00
https://programmers.co.kr/learn/courses/30/lessons/1829?language=java
코딩테스트 연습 - 카카오프렌즈 컬러링북
6 4 [[1, 1, 1, 0], [1, 2, 2, 0], [1, 0, 0, 1], [0, 0, 0, 1], [0, 0, 0, 3], [0, 0, 0, 3]] [4, 5]
programmers.co.kr
2021-06-27
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import java.util.Arrays;
import java.util.LinkedList;
import java.util.Queue;
public class Solution1829 {
public static boolean[][] vtd;
public static int[] dx = {-1, 0, 1, 0};
public static int[] dy = {0, -1, 0, 1};
public static int solve(int m, int n, int[][] picture, int x, int y) {
Queue<int[]> q = new LinkedList<>();
q.add(new int[]{x, y});
vtd[x][y] = true;
int color = picture[x][y];
int size = 1;
while(!q.isEmpty()) {
int[] tmp = q.poll();
int xx = tmp[0];
int yy = tmp[1];
for(int i = 0; i < 4; i++) {
int nx = xx + dx[i];
int ny = yy + dy[i];
if(nx < 0 || ny < 0 || nx >= m || ny >= n || vtd[nx][ny] || color != picture[nx][ny]) continue;
vtd[nx][ny] = true;
q.add(new int[]{nx, ny});
size++;
}
}
return size;
}
public static int[] solution(int m, int n, int[][] picture) {
int numberOfArea = 0;
int maxSizeOfOneArea = 0;
int[] answer = new int[2];
vtd = new boolean[m][n];
for(int i = 0; i < m; i++) {
for(int j = 0; j < n; j++) {
if(picture[i][j] != 0 && !vtd[i][j]) {
int size = solve(m, n, picture, i, j);
numberOfArea++;
maxSizeOfOneArea = Math.max(maxSizeOfOneArea, size);
}
}
}
answer[0] = numberOfArea;
answer[1] = maxSizeOfOneArea;
return answer;
}
public static void main(String[] args) {
int m = 6;
int n = 4;
int[][] pic = {{1, 1, 1, 0}, {1, 2, 2, 0}, {1, 0, 0, 1}, {0, 0, 0, 1}, {0, 0, 0, 3}, {0, 0, 0, 3}};
System.out.println(Arrays.toString(solution(m, n, pic)));
}
}
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cs |
#문제풀이
BFS로 같은 영역 찾으면 된다.